Answer:
30643 J
Step-by-step explanation:
= Vacuum permeability =
![4\pi * 10^(-7)\ H/m](https://img.qammunity.org/2020/formulas/physics/college/4f0xg4yq277gbzbiyeqdramqnjbsxfvnl2.png)
t = Time taken = 1 ns
c = Speed of light =
![3* 10^8\ m/s](https://img.qammunity.org/2020/formulas/physics/high-school/ks86dmym7sxdf8u3g31nulpxe5c16w96hm.png)
= Maximum electric field strength =
![1.52* 10^(11)\ V/m](https://img.qammunity.org/2020/formulas/physics/college/nv1uyd9pay0e0a9yvkfddh5thdwn5c2lhj.png)
A = Area =
![1\ mm^2](https://img.qammunity.org/2020/formulas/physics/college/ktm4i4l989llqc2y1zbosmqmzjvhswbhki.png)
Magnitude of magnetic field is given by
![B_0=(E_0)/(c)\\\Rightarrow B_0=(1.52* 10^(11))/(3* 10^8)\\\Rightarrow B_0=506.67\ T](https://img.qammunity.org/2020/formulas/physics/college/eeflss8pk56fif4ln7s2x5x6bk5attlqwx.png)
Intensity is given by
![I=(cB_0^2)/(2\mu_0)\\\Rightarrow I=(3* 10^8* 506.67^2)/(2* 4\pi * 10^(-7))\\\Rightarrow I=3.0643* 10^(19)\ W/m^2](https://img.qammunity.org/2020/formulas/physics/college/9j1e8i6uiouqx0qpzwz2351ddg1g16qxvv.png)
Power, intensity and time have the relation
![E=IAt\\\Rightarrow E=3.0643* 10^(19)* 1* 10^(-6)* 1* 10^(-9)\\\Rightarrow E=30643\ J](https://img.qammunity.org/2020/formulas/physics/college/d8fs2x1m1mhq3lmrn22f7xx8afxarek5ru.png)
The energy it delivers is 30643 J