Answer:
The first contribution was 637.77
Explanation:
Geometric Sequences
It a type sequence in which each term is computed as the previous term by a constant number. The general expression for a geometric sequence is
![\displaystyle a_n=a_1.r^(n-1),\ n>0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wxtfrmvzyh4cn9gts2arz77ugpot8r73c9.png)
If we know two terms of the sequence, say n=k and n=p, then
![\displaystyle a_k=a_1.r^(k-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yfc8fvf5ofhn8rbu06wz20538p41qx31mn.png)
and
![\displaystyle a_p=a_1.r^(p-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/igtiyp5cd5fsll3yx7d3puwpsbf5y531z8.png)
We can determine the values of
and r, by manipulating both equations
We know that
![a_(20)=483,\ a_(43)=345,\ so](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z3s8s3zkvru56ogxbknrgr9jpuvv39th16.png)
![\displaystyle a_(20)=483=a_1.r^(20-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dw1vxzyi0h307otlyqvshd62zylqa05vo2.png)
![\displaystyle a_(43)=345=a_1.r^(43-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qigu2wd9hqdc79wpxm9mwthi8auu92o5d7.png)
Dividing both expressions, we have
![\displaystyle (a_(43))/(a_(20))=(r^(42))/(r^(19))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mgjizq1ixyspgqwqq3nus55bgjoqqbf7gj.png)
Solving for r
![\displaystyle r^(23)=(345)/(483)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uophyjekfiuj6obu2o8o0qpj0cjdpo48di.png)
![\displaystyle r=\sqrt[23]{(345)/(483)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z4c9w1dcohdwhimiv391qw8g3p82swbv7c.png)
![\displaystyle r=0.9855](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vl23e0wicxozxepfc50m91oe4gti1h05z4.png)
Now we use
![\displaystyle a_(20)=483=a_1.r^(20-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dw1vxzyi0h307otlyqvshd62zylqa05vo2.png)
to compute
![a_1](https://img.qammunity.org/2020/formulas/mathematics/high-school/d6f53c0bf7h94zwlwkkooj07ybuvj6iivt.png)
![\displaystyle a_1=(a_(20))/(r_(19))=(483)/(0.9855^(19))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yv0lwest36brmro3dtwg4h8dtyhtd3d3i4.png)
![\boxed{a_1=637.77}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/oj19b0kza6ua6j0b8f2cejdu6vdyfqx137.png)