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Simplify the expression state any excluded values
2a^2-4a+2
---------------
3a^2-3

User CleoR
by
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2 Answers

2 votes

Answer:

3

Explanation:

User Bogdacutu
by
8.3k points
0 votes

Answer:

The simplified form is
(2(x-1))/(3(x+1)).


x =1 is the excluded value for the given expression.

Explanation:

Given:

The expression given is:


(2a^2-4a+2)/(3a^2-3)

Let us simplify the numerator and denominator separately.

The numerator is given as
2a^2-4a+2

2 is a common factor in all the three terms. So, we factor it out. This gives,


=2(a^2-2a+1)

Now,
a^2-2a+1=(a-1)(a-1)

Therefore, the numerator becomes
2(a-1)(a-1)

The denominator is given as:
3a^2-3

Factoring out 3, we get


3(a^2-1)

Now,
a^2-1 is of the form
a^2-b^2=(a-b)(a+b)

So,
a^2-1=(a-1)(a+1)

Therefore, the denominator becomes
3(a-1)(a+1)

Now, the given expression is simplified to:


(2a^2-4a+2)/(3a^2-3)=(2(x-1)(x-1))/(3(x-1)(x+1))

There is
(x-1) in the numerator and denominator. We can cancel them only if
x\\e1 as for
x=1, the given expression is undefined.

Now, cancelling the like terms considering
x\\e1, we get:


(2a^2-4a+2)/(3a^2-3)=(2(x-1))/(3(x+1))

Therefore, the simplified form is
(2(x-1))/(3(x+1))

The simplification is true only if
x\\e1. So,
x =1 is the excluded value for the given expression.

User Claudiu Iordache
by
8.9k points

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