Answer:
The three points on the line are (-1,-2), (0, -1), and (1, 0).
The graph is shown below.
Explanation:
Given:
The equation to graph is given as:
![x-y=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6y6exdtoaof5nmlx289zid7qeqz3x3bxqj.png)
In order to find three points on it, we choose three random values of 'x' and find the corresponding 'y' value from the equation and then plot the three points on the graph. After plotting the points, we join them to form a line.
The line drawn will represent the line of the given equation.
Let
![x=0](https://img.qammunity.org/2020/formulas/mathematics/high-school/7hekn15849nfrz752rdve3zqw7fwnla263.png)
So,
![0-y=1\\y=-1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/chau0o56aezb6pcbxs7b2pw67jtpf2e6pd.png)
Therefore, the first point is (0, -1)
Now, let
. So,
![1-y=1\\-y=1-1\\y=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cn8ze35hpbf0ngc2ixhn35cqvszgnvekh0.png)
Therefore, the second point is (1, 0)
Now, let
. So,
![-1-y=1\\y=-1-1\\y=-2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8b77di0kb8r6cjiiljs5mwvmp70sudh2tt.png)
Therefore, the third point is (-1, -2)
Now, mark these points on a graph and draw a line passing through all of these points. The line drawn is the graph of the given equation.
The graph is shown below.