Question

a solid circular shaft 150 mm diameter transmits a torque of 29820.586 N.m. find the maximum shear stress

Answer 1

45 Mpa

Step-by-step explanation:

The maximum shear stress,
`\tau_(max)`is given by

`\tau_(max)=\frac {16T}{\pi d^(3)}`

Where T is the torque and d is the diameter.

Substituting 29820.586 N.m for T and 0.15m for d then we obtain

`\tau_(max)=\frac {16* 29820.586}{\pi * 0.15^(3)}=44999999.22\approx 45 Mpa`