409,800 views
39 votes
39 votes
The diagram below shows the dimensions of a pool in a waterpark. Point "O" shown in the diagram is the center of the circular portion of the pool. If a cover is needed for the pool, what is the area of the cover?​ ​(Assume pi = 3.14) ​

The diagram below shows the dimensions of a pool in a waterpark. Point "O&quot-example-1
User Subodh
by
2.8k points

2 Answers

28 votes
28 votes

Answer:

hihihihi

Explanation:

User Lokinou
by
3.3k points
21 votes
21 votes

Answer:

10,168 sq m

Explanation:

The are of the cover is

the area of the circular portion of the pool + area of square portion - area common to both circular and square portions

The common portion is 1/4the the area of the circle

The radius of the circular portion = 80-40 = 40m

Area of circular portion = πr² = π (40)³ = 1600π sq m

1/4 this is 160/4 = 400 sq m

Area of square = 80² = 6400 sq m

Total area = 1600π + 6400 - 400π = 1200π + 6400 = 1200 x 3.14 + 6400

= 10,168 sq m

User Machine
by
2.5k points