Question

The sum of 5 consecutive integers is 110

Answer 1

Explanation:

Let the five consecutive integers be (x - 2 ) , (x - 1) , (x) , (x + 1) , (x + 2)

(x - 2 ) + (x - 1) + (x) + (x + 1) + (x + 2) = 110

x - 2 + x -1 + x + x +1 + x + 2 = 110

5x = 110

x = 110/5

x = 22

The consecutive numbers are: 20,21,22,23,24