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10 have volunteered to help with the preparations for a party. How many ways can Susan assign someone to buy​ beverages, someone to arrange for​ food, and someone to send the​ invitations? Assume that no person does two jobs.

User Kitswas
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1 Answer

3 votes

Answer:

The answer is 720 ways.

Explanation:

Total friends who volunteered = 10

Total number of jobs that have to be done = 3

Here order matters, so it is a permutation question.

We can use the formula nPr.

=
(10!)/(7!)

= 720 ways.

The second way to solve this is:

Susan can choose the first person to do a job in 10 ways

Then the second job can be done in 9 ways and the third in 8 ways.

Total becomes =
10*9*8=720 ways

User Noah Klayman
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5.7k points