Answer:
Therefore, height of the wall at which the ladder is placed is AB = 39.12 foot.
Explanation:
Let,
AB = height of the wall at which the ladder is placed
AC = height of the ladder = 40 foot
BC = distance from the wall to the base of the ladder = 8 feet
To Find:
AB = height of the wall at which the ladder is placed = ?
Solution:
Consider a right angled triangle Δ ABC right angle at angle B,
So by Pythagoras theorem we have
![(\textrm{Hypotenuse})^(2) = (\textrm{Shorter leg})^(2)+(\textrm{Longer leg})^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zzqkt74bo8i0g39uk3gex0h5896knh6wio.png)
AC² = AB² + BC²
Substituting the given values in above equation we get
40² = AB² + 8²
∴ AB² = 40² - 8²
∴ AB² = 1536
![\therefore AB =\pm√(1536) \\\\(distance\cannot\ be\ negative)\\\therefore AB =39.19\ foot\\](https://img.qammunity.org/2020/formulas/mathematics/middle-school/q6jkn9z6avvdgogeu9jdbccr76342wovfv.png)
Therefore, height of the wall at which the ladder is placed is AB = 39.12 foot.