Question

Express log2 6 + log2 7 as a single logarithm. A. log2 42 B. log2 √ 42 C. log2 7/6 D. log2 6/7

Answer 1

A.
`\log _2\left(6\right)+\log _2\left(7\right)=\log _2\left(42\right)`

Explanation:

To express
`\log _2\left(6\right)+\log _2\left(7\right)` as a single logarithm you must apply the log rule:

`\log _c\left(a\right)+\log _c\left(b\right)=\log _c\left(ab\right)`

So,

`\log _2\left(6\right)+\log _2\left(7\right)=\log _2\left(6\cdot \:7\right)`

Multiply the numbers:
`6\cdot \:7=42`

`\log _2\left(6\right)+\log _2\left(7\right)=\log _2\left(42\right)`