Question

Tendons are strong elastic fibers that attach muscles to bones. To a reasonable approximation, they obey Hooke's law. In laboratory tests on a particular tendon, it was found that, when a 251 g object was hung from it, the tendon stretched 1.23 cm .Find the force constant of this tendon.

Answer 1

k = 200 N/m

Step-by-step explanation:

given,

mass of the object = 251 g

= 251 x 10⁻³ Kg = 0.251 Kg

distance of tendon stretch = x = 1.23 cm

= 1.23 x 10⁻² = 0.0123 m

using the formula

F = k x

where

k is the force constant of the tendon

F = m g

F = 0.251 x 9.8 = 2.4598 N

2.4598 = k x 0.0123

k = 199.98 N/m

k = 200 N/m

hence, force constant of the tendon is approximately equal to 200 N/m