Answer:
The other angle is 120°.
Step-by-step explanation:
Given that,
Angle = 60
Speed = 5.0
We need to calculate the range
Using formula of range
...(I)
The range for the other angle is
....(II)
Here, distance and speed are same
On comparing both range
![(v^2\sin(2\theta))/(g)=(v^2\sin(2(\alpha-\theta)))/(g)](https://img.qammunity.org/2020/formulas/physics/high-school/fxovsdaftdi4zujwbnjpuby520la46jrqb.png)
![\sin(2\theta)=\sin(2*(\alpha-\theta))](https://img.qammunity.org/2020/formulas/physics/high-school/pvc7fam7y19xmj4zkc94uqbdbnez18h0dn.png)
![\sin120=\sin2(\alpha-60)](https://img.qammunity.org/2020/formulas/physics/high-school/u4vl6l785myrz9y865qzo1euiddymjhqtx.png)
![120=2\alpha-120](https://img.qammunity.org/2020/formulas/physics/high-school/jb5czal6njt3zuhzbrlksag2arf79awigr.png)
![\alpha=(120+120)/(2)](https://img.qammunity.org/2020/formulas/physics/high-school/7241cagsyf8i80fdd0ek2ay6qk34znmqxz.png)
![\alpha=120^(\circ)](https://img.qammunity.org/2020/formulas/physics/high-school/zascn95hj4ljwhc2udqv0mr9tm880bv027.png)
Hence, The other angle is 120°