Empirical formula C2H2O Experimental molar mass 216 g/mol

Question

asked Jan 19, 2020 114k views

1 Answer

Manderson · Answer 1 · 2020-01-24T13:55:18+0000

Answer:

Molecular formula of the compound is

Step-by-step explanation:

Empirical formula of the given compound -
C_(2)H_(2)O

Empirical formula mass =
(2* 12g/mol)+(2* 1g/mol)+(16 g/mol)=42g/mol

$(Molecular\,formula\,mass)/(Empirical\,formula\,mass)=(216g/mol)/(42g/mol)$

$(Molecular\,formula\,mass)/(Empirical\,formula\,mass)=(216g/mol)/(42g/mol)= 5.15=5$

${Molecular\,formula}= 5* {Empirical\,formula}$

= 5* C_(2)H_(2)O=C_(10)H_(10)O_(5)

Therefore, molecular formula of the compound is
C_(2)H_(2)O=C_(10)H_(10)O_(5)