Question

Empirical formula C2H2O
Experimental molar mass 216 g/mol

Answer 1

Molecular formula of the compound is
`C_(2)H_(2)O=C_(10)H_(10)O_(5)`

Step-by-step explanation:

Empirical formula of the given compound -
`C_(2)H_(2)O`

Empirical formula mass =
`(2* 12g/mol)+(2* 1g/mol)+(16 g/mol)=42g/mol`

`(Molecular\,formula\,mass)/(Empirical\,formula\,mass)=(216g/mol)/(42g/mol)`

`(Molecular\,formula\,mass)/(Empirical\,formula\,mass)=(216g/mol)/(42g/mol)= 5.15=5`

`{Molecular\,formula}= 5* {Empirical\,formula}`

`= 5* C_(2)H_(2)O=C_(10)H_(10)O_(5)`

Therefore, molecular formula of the compound is
`C_(2)H_(2)O=C_(10)H_(10)O_(5)`