Question

UVC light used in sterilizers, has wavelengths between 100 to 280 nm. If a certain UVC wave has a wavelength of 219 nm, what is the energy of one of its photons in J? Once you have the value, take it log (base 10) and enter that with three decimal places as your answer. Do not enter units.

Answer 1

-18.042

Step-by-step explanation:

A photon is refer to as a particle of light with a discrete bundle of electromagnetic energy. Photon is always in motion and in a vacuum with a constant light speed to all viewers. The amount of energy of the photon (E) is calculated using:

`E = (h*c)/(wavelength)`

Where:

h is Planck's constant =
`6.63*10^(-34) Js`

c is the speed of light = 299792458 m/s

wavelength = 219 nm =
`219*10^(-9)` m

Therefore, the amount of energy of the photon is:

`E =(6.63*10^(-34)*299792458 )/(219*10^(-9) ) = 9.076*10^(-19) J`

Taking the log (base 10) of the value of the energy, we have:

log (base 10)
`9.076*10^(-19) = - 18.0421`

Thus, the answer in three decimal places is -18.042

Answer 2

-18.042

Step-by-step explanation:

We can find the energy of a photon (E) using the Planck-Einstein equation.

E = h . ν = h . c . λ⁻¹

where,

h is the Planck's constant

ν is the frequency

c is the speed of light

λ is the wavelength

E = (6.63 × 10⁻³⁴ J.s) × (3.00 × 10⁸ m/s) × (219 × 10⁻⁹ m)⁻¹ = 9.08 × 10⁻¹⁹ J

log (9.08 × 10⁻¹⁹) = -18.042