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A 1,492.3-kg airplane travels down the runway. Each of its four engines provides a force of

1,447.5 N. Find the acceleration of the airplane, in m/s2. (Ignore friction.)

User Pubby
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1 Answer

5 votes

Answer:

The acceleration of the plane is, a = 3.88 m/s²

Step-by-step explanation:

Given data,

The mass of the airplane, m = 1492.3 kg

The force produced by each engine, f = 1447.5 N

Therefore, the total force produced by four engines, F = 5790 N

The force acting on an object is equal to the product of its mass and acceleration,

F = ma

Therefore, the acceleration is

a = F/m

Substituting the given values in the above equation,

a = 5790 N / 1492.3 kg

a = 3.88 m/s²

Hence, the acceleration of the plane is, a = 3.88 m/s²

User Chris Allen Lane
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