Answer:
The acceleration of the truck is, a = - 0.2 m/s²
Step-by-step explanation:
Given data,
The initial velocity of the truck, u = 14 m/s
The final velocity of the truck, v = 10 m/s
The time taken by the truck to reduce its velocity, t = 20 s
Using the first equations of motion,
v = u + at
![a=(v-u)/(t)](https://img.qammunity.org/2020/formulas/physics/middle-school/rbz9i28f98a6dvpx0ghax9pxq7qjfdf5sd.png)
Substituting the given values,
![a=(10-14)/(20)](https://img.qammunity.org/2020/formulas/physics/middle-school/rdx64cbifric4mm5eo2yb2pt3s9jgrolh0.png)
a = - 0.2 m/s²
The negative sign in the acceleration indicates that the truck is decelerating.
Hence, the acceleration of the truck is, a = - 0.2 m/s²