Question

What is the change in temperature if
2355 cal heats 51.5 g of water?

Answer 1

45.73°C

Step-by-step explanation:

Given parameters:

Quantity of heat = 2355cal

Mass of water = 51.5g

Unknown:

Change in temperature = ?

Solution:

To solve this problem, use the expression below;

H = m c Ф

H is the quantity of heat

m is the mass

c is the specific heat of water = 1cal/g°C

Ф is the change in temperature = ?

Now insert the parameters and solve;

H = 51.5 x 1 x Ф

2355 = 51.5 x Ф

Ф = 45.73°C