Question

A jogger jogs from one end to the other of a straight track in 1.17 min and then back to the starting point in 1.58 min. What is the jogger's average speed at the following points? (Assume the track is 100 m long.)

(a) in jogging to the far end of the track
m/s

(b) coming back to the starting point
m/s

(c) for the total jog
m/s

Answer 1

A- 1.4 m/s


Explanation: first you convert minutes to seconds (x60) 1.17m x 60= 70.2 s. to calculate average speed you do distance/time. So you would do 100 m/70.2s = 1.4 m/s

B- 1.05 m/s

Explanation: first you convert minutes to seconds. 1.58m x 60= 94.8s. to calculate the average speed you do distance/ time. 100/ 94.8= 1.05 m/s

C- 0.6 m/s

Explanation: add the times together 70.2s + 94.8s= 165 s
to find the average speed you divide total distance by total time 100m/165s= 0.6 m/s