Answer:
25.25%
Step-by-step explanation:
Mean diameter (μ) = 0.35 inches
Standard deviation (σ) = 0.03 inches
For any given diameter, X, the z-score is given by:
![z=(X-\mu)/(\sigma)](https://img.qammunity.org/2020/formulas/mathematics/high-school/yy1zf274lzdoya3jdowvpkawdx5s5b0sce.png)
For X= 0.37 inches:
![z=(0.37-0.35)/(0.03)\\z=0.6667](https://img.qammunity.org/2020/formulas/physics/college/21qj7f6eic4y53sx8bg77pz675efb3d0fx.png)
A z-score of 0.6667 is equivalent to the 74.75-th percentile of a normal distribution.
Therefore, the percentage of bolts that will have a diameter greater than 0.37 inches is:
![P(X>0.37) = 100 - 74.75\\P(X>0.37) = 25.25\%](https://img.qammunity.org/2020/formulas/physics/college/5nh4he2uwvreq9rb8cmagio6zyq0gng3am.png)