Question

Phosphine, an extremely poisonous and highly reactive gas, will react with oxygen to form tetraphosphorus decaoxide and water. PH3(g) + O2(g) → P4O10(s) + H2O(g) [unbalanced]Calculate the mass of P 4O 10( s) formed when 225 g of PH 3 reacts with excess oxygen

Answer 1

The mass of P₄O₁₀ (s) formed is 471.03 g

Step-by-step explanation:

4PH₃(g) + 8O₂(g) → P₄O₁₀ (s) + 6H₂O (g)

This is the ballanced equation.

Every 4 moles of phosphine, 1 mol of tetraphosphorus decaoxide is generated.

Moles of PH₃ = Mass PH₃ / Molar mass PH₃

Moles PH₃ = 225 g / 33.9 g/m

Moles PH₃ = 6.63 moles

So the rule of three, will be:

If 4 moles of PH₃ generate 1 mol P₄O₁₀

Then, 6.63 moles of PH₃ generate (6.63 .1)/4 = 1.66 moles

If we want to know the mass:

Moles . Molar mass = mass

Molar mass P₄O₁₀ = 283.88 g/m

1.66m . 283.88 g/m = 471.03 g