Question

A glass ball of radius 3.74 cm sits at the bottom of a container of milk that has a density of 1.04 g/cm3. The normal force on the ball from the container's lower surface has magnitude 9.03 x 10-2 N. What is the mass of the ball?

Answer 1

The mass of the ball is 0.23 kg

Step-by-step explanation:

Given that

radius ,r= 3.74 cm

Density of the milk ,ρ = 1.04 g/cm³ = 1.04 x 10⁻³ kg/cm³

Normal force ,N= 9.03 x 10⁻² N

The volume of the ball V

`V=(4)/(3)\pi r^3`

`V=(4)/(3)* \pi * 3.74^3\ cm^3`

V= 219.13 cm³

The bouncy force on the ball = Fb

Fb = ρ V g

Fb + N = m g

m=Mass of the ball = Density x volume

m = γ V , γ =Density of the Ball

ρ V g + N = γ V g ( take g= 10 m/s²)

`\gamma =(N+\rho V g)/(V g)`

`\gamma =(9.03* 10^(-2)+1.04* 10^(-3)* 219.13*  10)/(219.13* 10)`

γ = 0.00108 kg/cm³

m = γ V

m = 0.00108 x 219.13

m= 0.23 kg

The mass of the ball is 0.23 kg