Answer:
The system of equation that represent this situations are;
![\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.](https://img.qammunity.org/2020/formulas/mathematics/high-school/2caioj42zfq9z0ioqibbkgncd2xt3nsyea.png)
Also 5 hats and 10 scarves can be prepared from 2 kg of yarn.
Explanation:
Let number of hat Chevy makes be h.
Also Let number of scarves Chevy makes be s.
Given:
Total Amount of yarns = 2 kg
Total number of items = 15
Since Items need to make are hat and scarves.
Hence the equation can be represented as;
![h+s=15 \ \ \ \ equation \ 1](https://img.qammunity.org/2020/formulas/mathematics/high-school/5lifdd64czieu0ofgrgzbt8x8hqwez9x74.png)
Again Given:
Each hat uses 0.2 kilograms of yarn.
each scarf uses 0.1 kilograms of yarn.
Hence the equation can be represented as;
![0.2h+0.1s=2 \ \ \ \ \ equation \ 2](https://img.qammunity.org/2020/formulas/mathematics/high-school/4n935p2u6kbj08pkg1m3rqq6k2n6ufng54.png)
Hence the system of equation that represent this situations are;
![\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.](https://img.qammunity.org/2020/formulas/mathematics/high-school/2caioj42zfq9z0ioqibbkgncd2xt3nsyea.png)
Now Solving these to find number of hats and number of scarves.
Multiplying equation 2 with 10 we get;
![10(0.2h+0.1s)=2* 10\\10*0.2h+10*0.1s=20\\2h+s =20 \ \ \ \ \ equation \ 3](https://img.qammunity.org/2020/formulas/mathematics/high-school/mpqmlap45ep10w4wy28s1q77v1j9yfrcne.png)
Now Subtracting equation 1 from equation 3 we get;
![(2h+s)- (h+s) =20-15\\2h+s-h-s=5\\h= 5](https://img.qammunity.org/2020/formulas/mathematics/high-school/5gr0hdzhmdcwpmzbu2kwb3asw786jwjqi9.png)
Now Substituting the value of h in equation 1 we get;
![h+s= 15\\5+s =15\\s=15-5\\s=10](https://img.qammunity.org/2020/formulas/mathematics/high-school/n430nt3h4oyek55q07s8eon2ptuwhqgyv0.png)
Hence 5 hats and 10 scarves can be prepared from 2 kg of yarn.