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What is the distance, in units, between the points (5,2) and (-3,6) in the standard (x,y) coordinate plane?

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Answer:


d=√(80)\ units

Explanation:

Distance In The XY Plane

Given two points in the plane (a,b) and (c,d), the distance between them is computed by


d=√((c-a)^2+(d-b)^2)

The points are (5,2) and (-3,6), so a=5, b=2, c=-3, d=6


d=√((-3-5)^2+(6-2)^2)


d=√((-8)^2+(4)^2)


d=√(64+16)


d=√(80)\ units

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