Answer:
Gravitational potential Energy change of the ball after, 10m= 98J
Step-by-step explanation:
A 1 kg ball is dropped from the top of a cliff and falls with a constant acceleration due to gravity (9.8 m/s2). Assume that effects of air resistance can be ignored. a.) By how much has the ball's gravitational potential energy changed after it has fallen by 10 m
Gravitational Potential Energy: This is the energy a body posses by virtue of it's position in a gravitational field. It is measured in Joules.
Gravitational potential Energy = Mass(m) × acceleration due to gravity (g) × Height(h) = mgh
Where m = 1kg, g = 9.8 m/s², h =10 m
∴ Gravitational potential Energy change of the ball after, 10m = 1 × 9.8 × 10 = 98 J