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Please help me with both of these questions I’m supper stuck

Please help me with both of these questions I’m supper stuck-example-1

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Answer:

ONE SOLUTION

Explanation:

When two points on a line are given, the equation of the line is given by the formula:


$ (y - y_1)/(y_2 - y_1) = (x - x_1)/(x_2 - x_1) $

where
$ (x_1, y_1) $ and
$ (x_2, y_2) $ are the points on the line.

Here, the first set of points are:
$ (-1, 3) $ and
$ (0, 1) $.

Therefore,
$ (x_1, y_1) = (-1, 3) $ and
$ (x_2,y_2) = (0, 1) $.

The line passing through this is given by:


$ (y - 3)/(1 - 3) = (x + 1)/(1) $


$ \implies y - 3 = -2x - 2 $

∴ 2x + y - 1 =0

Now, for the second line, the points are:


$ (x_1, y_1) = (1, 4) $ and
$ (x_2, y_2) = (0, 2) $.

Therefore,
$ (y - 4)/(-2) = (x - 1)/(-1) $


$ \implies -y + 4 = -2x + 2 $

∴ 2x - y + 2 = 0

Now, to determine the number of solutions the two equations have, we solve these two equations,

Adding Eqn(1) and Eqn(2) we get:

4x = -1


$ \implies x = (-1)/(4) $

And
$ y = (3)/(2) $.

Since, we arrive at unique values of 'x' and 'y', we say the lines have only one unique solution.

User Farkhod  Daniyarov
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