Question

A watertight car is submerged under water. What force is required to open a door of area 1.13 m2 if the average depth of water at the door is 1.62 m?

Answer 1

17939.88 N

Step-by-step explanation:

`Pressure = (Force)/(Area)`

⇒
`P = (F)/(A)` ........(1)

Also, the pressure of a fluid is given as;

P = ρgh .......(2)

Where P is the pressure of the fluid

ρ is the density of the fluid ( in this question the fluid is water)

h is the height(depth) of the fluid

Equating equation (1) and (2)

`(F)/(A)` = ρgh

Force, F = ρghA

Given:

Area of the door A = 1.13m²

Depth of the water h = 1.62m

Density of water ρ = 1000kg/m³

Acceleration due to gravity g = 9.8m/s²

F = 1000 × 9.8 × 1.62 × 1.13

F = 17939.88 N

The force require to open the door is 17939.88 N