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A circle is centered at (2,-5) and has radius 3. Write its equation in standard form.

A)
(x + 2)2 + (y - 5)2 = 3
B)
(x - 2)2 + (y + 5)2 = 3
(x + 2)2 + (y - 5)2 = 9
(x - 2)² + (y + 5)² = 9

User Setmax
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1 Answer

4 votes

Answer:

Option (D) is correct


(x-2)^(2) +(y+5)^(2) = 9

Explanation:

A circle has (a , b ) are the coordinates of the centre and
r = radius .

Given.

A circle is centered at (2,-5) and has radius 3

Let
a=2 and
b=-5 and
r=3

The standard form of the circle is.


(x-a)^(2) +(y-b)^(2) = r^(2)------(1)

Put a, b and r value in equation 1.


(x-2)^(2) +(y-(-5))^(2)= 3^(2)


(x-2)^(2) +(y+5)^(2) = 9

So. the standard form of equation is.


(x-2)^(2) +(y+5)^(2)= 9

User Beto Neto
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