Question

A circle is centered at (2,-5) and has radius 3. Write its equation in standard form.

A)
(x + 2)2 + (y - 5)2 = 3
B)
(x - 2)2 + (y + 5)2 = 3
(x + 2)2 + (y - 5)2 = 9
(x - 2)² + (y + 5)² = 9

Answer 1

Option (D) is correct

`(x-2)^(2) +(y+5)^(2) = 9`

Explanation:

A circle has (a , b ) are the coordinates of the centre and
`r = radius` .

Given.

A circle is centered at (2,-5) and has radius 3

Let
`a=2` and
`b=-5` and
`r=3`

The standard form of the circle is.

`(x-a)^(2) +(y-b)^(2) = r^(2)`------(1)

Put a, b and r value in equation 1.

`(x-2)^(2) +(y-(-5))^(2)= 3^(2)`

`(x-2)^(2) +(y+5)^(2) = 9`

So. the standard form of equation is.

`(x-2)^(2) +(y+5)^(2)= 9`