Question

When 0.5141 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.823 °C to 29.419 °C. Find ΔrU and ΔrH for the combustion of biphenyl in kJ mol−1 at 298 K. The heat capacity of the bomb calorimeter, determined in a separate experiment, is 5.861 kJ °C−1.

Answer 1

The heat produced by the combustion of the benzene sample is 6.56376 kJ.

Step-by-step explanation:

To find the heat produced by the combustion of benzene, we can use the formula:

q = C_bomb * ΔT

Where q is the amount of heat produced, C_bomb is the heat capacity of the bomb calorimeter, and ΔT is the change in temperature. Rearranging the equation, we have:

q = C_bomb * ΔT

Substituting the given values, we get:

q = (784 J/°C) * (8.39 °C)

Calculating this value, we find that q is equal to 6563.76 J. To convert this to kJ, we divide by 1000:

q = 6563.76 J = 6.56376 kJ

Therefore, the heat produced by the combustion of the benzene sample is 6.56376 kJ.