Answer:
The molecular formula of this compound is
![H_(2)O_(2)](https://img.qammunity.org/2020/formulas/chemistry/high-school/mxppnzrnsxxtzty6qm6ln4zrv6rysxdv.png)
Step-by-step explanation:
From the given,
Mass of compound = 7.36 g
Molar mass of compound = 34.0 g/mol
The mass of oxygen = 6.93 g
The hydrocarbon contains only hydrogen and carbon.
Mass of hydrogen + Mass of oxygen = 7.36 g
Mass of hydrogen + 6.93 g = 7.36 g
Mass of hydrogen = 7.36 - 6.93 = 0.43g
Molar mass of hydrogen = 1.0 g/mol
Molar mass of oxygen = 16 g/mol
![Number\,of\,moles\,of \,Oxygen=6.93g*(1)/(16)=0.43mol](https://img.qammunity.org/2020/formulas/chemistry/middle-school/uinknshyvr29stzf2bgdr07rwnlspmt22d.png)
![Number\,of\,moles\,of \,hydrogen=0.43g*(1)/(1)=0.43mol](https://img.qammunity.org/2020/formulas/chemistry/middle-school/h44mudcp64tyx7iugm1ttsf7sga75iv94u.png)
Now divided each one by 0.43
Oxygen:
![(0.43)/(0.43)=1](https://img.qammunity.org/2020/formulas/chemistry/middle-school/fyrtufm3yvxylo4izcov2wotqyrcr54qot.png)
Hydrogen :
![(0.43)/(0.43)=1](https://img.qammunity.org/2020/formulas/chemistry/middle-school/fyrtufm3yvxylo4izcov2wotqyrcr54qot.png)