Question

20 liters of an incompressible liquid exert a force of 50 N on the surface of the Moon (g = 1.67 m/s2). What force will 7.6 liters of the liquid exert on the surface of the Earth?

Answer 1

111.50 N

Step-by-step explanation:

Volume on the moon = 20 L

Acceleration on the moon = g = 1.67 m/s2

Volume on Earth = 7.6 L

Acceleration on Earth = 9.8 m/s2

The force exerted by the liquid on the moon is given by:

`F_m=m*a_(moon)\\m=(50)/(1.67) \\m=29.94 kg`

An incompressible liquid has a constant density:

`\rho = (m)/(v) \\\rho = (29.94)/(20) \\\rho = 1.497\ kg/L`

The force exerted by 7.6 liters on Earth is:

`F=\rho*V*a_(Earth)\\F=1.497*7.6*9.8\\F=111.50\ N`