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One attorney claims that more than 25% of all the lawyers in Boston advertise for their business. A sample of 200 lawyers in Boston showed that 63 of the lawyers had used some form of advertising for their business. At ???? =0.05, is there enough evidence to support the attorney’s claim? (Use the P-value method to test this hypothesis)

User Shubhendu
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1 Answer

2 votes

Answer:

There is enough evidence to support the attorney’s claim

Explanation:

Given that one attorney claims that more than 25% of all the lawyers in Boston advertise for their business.

Sample size n =200

Sample proportion =
63/200=0.315

Hypotheses:


H_0: p=0.25\\H_a: p>0.25

(right tailed testat 5% significance level)

Assuming H0 to be true, std error of p =
\sqrt{0.25*0.75/200 \\=0.0306

Test statistic z = p diff/std error

=
(0.315-0.25)/(0.0306) \\=2.12

p value for one tailed =0.0170

Since p <0.05 we reject null hypothesis

There is enough evidence to support the attorney’s claim

User Roarster
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