Answer:
There is enough evidence to support the attorney’s claim
Explanation:
Given that one attorney claims that more than 25% of all the lawyers in Boston advertise for their business.
Sample size n =200
Sample proportion =
![63/200=0.315](https://img.qammunity.org/2020/formulas/mathematics/college/9qvpxxsap1uxdg4u7wnssqdoa1n3uqvymj.png)
Hypotheses:
![H_0: p=0.25\\H_a: p>0.25](https://img.qammunity.org/2020/formulas/mathematics/college/inakyjnixrwrb44rqhwpagw2uiwk9dukma.png)
(right tailed testat 5% significance level)
Assuming H0 to be true, std error of p =
![\sqrt{0.25*0.75/200 \\=0.0306](https://img.qammunity.org/2020/formulas/mathematics/college/m8rgmpofxweng9lgiw3rejrt9lkf5h5dyr.png)
Test statistic z = p diff/std error
=
![(0.315-0.25)/(0.0306) \\=2.12](https://img.qammunity.org/2020/formulas/mathematics/college/cg8ecysj8d6jlc9320tipnk4o4ghayxgu4.png)
p value for one tailed =0.0170
Since p <0.05 we reject null hypothesis
There is enough evidence to support the attorney’s claim