Question

A triangle has side lengths 6, 7, and B, and the angle between the sides of lengths 6 and 7 measures 60 degress. If A si the area of the triangle and B is the integer closet B, find the value of A/b.

Answer 1

The value of A/b is 2.60

Explanation:

We have cosine formula

c² = a² + b² - 2ab cosC

Here

c = B

a = 6

b = 7

C = 60°

Substituting

B² = 6² + 7² - 2 x 6 x 7 cos60

B² = 43

B = 6.56

b = 7 closest integer to B.

Given that A is area of triangle

A=0.5absinC

A = 0.5 x 6 x 7 x sin60 = 18.19

We need to find
`(A)/(b)`

`(A)/(b)=(18.19)/(7)=2.60`

The value of A/b is 2.60