Question

The point (-2,2) is one endpoint of a segment that has a length of 10.049 units. The other endpoint is in quadrant 3 and has an x-coordinate od -3. What is the y-coordinate of the endpoint in quadrant 3

Answer 1

The y coordinate is -7.999 ≈ -8

Explanation:

One of the points on line segment is given as (-2,2).

The distance given is 10.049 units.

The x coordinate of other point is given as -3. Thus the point is (-3 , y),

where y is y coordinate of point lying in third quadrant.

The distance formula is given as,

Distance =
`\sqrt{(x1-x2)^(2) + (y1-y2)^(2)}`, where

(x1,y1) and (x2,y2) are endpoints of line segment.

Inserting above two points and equating to 10.049 units,

`10.049 = \sqrt{((-2)-(-3))^(2) + ((2)-y)^(2)}`

Squaring both the sides,

`100.982 = (1)^(2) + ((2)-y)^(2)`

`99.982 = ((2)-y)^(2)`

+9.999 = (2-y) or -9.999 = (2-y)

y = 2-9.999 or y = 2+9.999

y = - 7.999 0r 11.999

But, point lies in third quadrant and is negative.

thus, y = -7.999