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Ten days after it was launched toward Mars in December 1998, the Mars Climate Orbiter spacecraft (mass 629 kg) was 2.87×10⁶ km from the earth and traveling at 1.20×10⁴ km/h relative to the earth.At this time, what were (a) the spacecraft’s kinetic energy relative to the earth and (b) the potential energy of the earth–spacecraft system?

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Answer:


(a)K.E=3.49*10^(9)J\\ (b)P.E=-8.73*10^(7)J

Step-by-step explanation:

Given data

mass=629 kg


distance=2.87*10^(6)km\\ v=1.20*10^(4)(km)/(h)\\  K.E=?\\P.E=?

Sokution

For (a) K.E


K.E=(1)/(2)mv^(2)\\  as \\v=1.20*10^(4)(km)/(h)=3.33*10^(3)(m)/(s)\\    K.E=(1/2)*(629)*(3.33*10^(3))^(2)  \\K.E=3.49*10^(9)J

For (b) P.E


P.E=(-G*m(orbiter)*m(earth))/(r)\\ P.E=(-(6.67*10^(-11) )*(629)*(5.97*10^(24) ))/(2.89*10^(9) )\\ P.E=-8.73*10^(7)J

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