Answer:
![(0.099,\ 0.157)](https://img.qammunity.org/2020/formulas/mathematics/college/vjp2mannk2gg6urur9x471fg0u0ppw2967.png)
Explanation:
We know that the confidence interval for population standard deviation is given by :-
, where , n= sample size.
= sample proprotion.
z* = critical z-value.
Given : A random sample of 500 registrations are selected from a Department of Motor Vehicles database, and 64 are classified as sports utility vehicles.
i.e. n= 500
![\hat{p}=(64)/(500)=0.128](https://img.qammunity.org/2020/formulas/mathematics/college/7upkezi5smdmgwavjsbw6408915zmhst4v.png)
We know that critical z-value for 95% confidence = z*=1.96
Then, the 95% confidence interval to estimate the proportion of sports utility vehicles in California will be :-
Hence, the 95% confidence interval to estimate the proportion of sports utility vehicles in California. =
![(0.099,\ 0.157)](https://img.qammunity.org/2020/formulas/mathematics/college/vjp2mannk2gg6urur9x471fg0u0ppw2967.png)