Answer:
OPTION D
Explanation:
We have to determine which option determines the function given above.
To determine the function, just substitute the values and compare LHS and RHS.
we have
![$ f(4) = 18 $](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kuxwk6bqnqktmwzqomf60qhuqjkb9qylyb.png)
![$ f(-2) = -12 $](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nn9uwpltbt5eyyhu8h1pv9ngw7yx2c0zuy.png)
![$ f(0) = -2 $](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qfvazho79z48muumsbqnyfl969ys484aig.png)
![$ f(-3) = -17 $](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tsxpae4rn433ctt1bzy7bfhhgweza72u07.png)
Here,
is the domain and
is the co-doamin.
Therefore,
![$ x = \{4, -2, 0, -3\} $](https://img.qammunity.org/2020/formulas/mathematics/middle-school/39zxgwsnsfut98k6ttgf94puhc7cptvwua.png)
Now, OPTION A:
![$ f(x) = 2x - 5 $](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pzw1k3l8gybqqu40lo7sxmqayr7vg8p9ws.png)
Substitute x = 4. We get f(x) = 3
18.
So, OPTION A is rejected.
Similarly, OPTION B:
![$ f(x) = 5x + 2 $](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n8iqd69pk0fpayyas4p53l1f82qfyv0omn.png)
Substitute x = 4. We get f(4) = 22
18.
It is rejected as well.
Now, for OPTION C:
![$ f(x) = (x)/(2) - 5 $](https://img.qammunity.org/2020/formulas/mathematics/middle-school/c89b6gp1v8i5ifwkowuwkj1vb44ja0m0fs.png)
Substitute x = 4. We get f(4) = -3
18.
So, OPTION C is also rejected.
OPTION D:
![$ f(x) = 5x - 2 $](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z4myxnjrltoprujhthlvho6nebc5wso1pq.png)
Substitute x = 4. We get f(4) = 18.
Substitute the remaining points in domain as well. We notice that it exactly matches the given function. So, OPTION D is the answer.