Answer:
Thus, the coffee shop is willing to supply 6 pounds per week at a price of $4 per pound.
Explanation:
We are given the following information in the question:
The marginal price per pound (in dollars) is given by:
![p'(x) = \displaystyle(208)/((x+7)^2)](https://img.qammunity.org/2020/formulas/mathematics/college/4n4khnix660njac913zj1034fe5yvjqow1.png)
where x is the supply in pounds.
![P(x) = \displaystyle\int p'(x)~dx =\displaystyle\int\displaystyle(208)/((x+7)^2)~dx\\\\P(x) = (-208)/((x+7)) + c\\\\\text{where c is the constant of integration.}](https://img.qammunity.org/2020/formulas/mathematics/college/rd2ex6ep74iuxitjqjp39444e865cjfrec.png)
The coffee shop is willing to supply 9 pounds per week at a price of $7 per pound.
Thus, we are given that
P(9) = 7
Putting the values, we get,
![P(x) = \displaystyle(-208)/((x+7)) + c\\\\P(9) = 7\\\\\displaystyle(-208)/((9+7)) + c = 7\\\\c = 7 + (208)/(16) = 20](https://img.qammunity.org/2020/formulas/mathematics/college/advg589x3ezf8r2e8j5s22avet4ykikxas.png)
![P(x) = \displaystyle(-208)/((x+7)) + 20](https://img.qammunity.org/2020/formulas/mathematics/college/c4h2419gsl5s3ayan4bwq7vauvu0iee4my.png)
Now, we have to find how many pounds it would be willing to supply at a price of $4 per pound.
P(x) = 4
![P(x) = \displaystyle(-208)/((x+7)) + 20 = 4\\\\(-208)/(x+7) = -16\\\\x + 7 = 13\\x = 6](https://img.qammunity.org/2020/formulas/mathematics/college/vkjiy8ds98i7t6zg70ttrvecimzyj4clz8.png)
Thus, the coffee shop is willing to supply 6 pounds per week at a price of $4 per pound.