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Solve the following system of equations by the substitution method. 10x+10y=1.

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Answer:

Since one equation already has one variable isolated(x), it gives you a "value" to input into the other equation to use to solve for the other variable(y).

10(y-3) + 10y = 1

10y - 30 + 10y = 1

20y - 30 = 1

20y = 31

y = 31/20 or 1.55

Now you can use this value to solve for x in one of the original equations.

x = (31/20) - 3

x = -29/30 or -1.45

Hope this helps!

Explanation:

User Pieter Meiresone
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