Answer:
129 g
Step-by-step explanation:
The radioactive decay of a substance can be represented through the following expression.
![A=A_(0).e^(-k.t)](https://img.qammunity.org/2020/formulas/chemistry/college/xguzvh0qdhphv2gm2a9e9grrk8shr8xabt.png)
where,
A is the amount of A at certain time t
A₀ is the initial amount of A
k is the rate constant
We can find k from the half-life (t1/2) using the following expression.
![t_(1/2)=(ln2)/(k) \\k=(ln2)/(t_(1/2)) =(ln2)/(3.20h) =0.217h^(-1)](https://img.qammunity.org/2020/formulas/chemistry/college/s6mzvhdfr1b58uo2zuofdzejousik88dp0.png)
If 22.8 g of the substance is currently present, what mass A₀ was present 8.00 hours ago?
![A=A_(0).e^(-k.t)\\22.8g = A_(0).e^{-0.217h^(-1)* 8.00h} \\A_(0)=129g](https://img.qammunity.org/2020/formulas/chemistry/college/8yv3l9554b4jcfqn06cb18vhnbugko6tos.png)