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An unknown radioactive substance has a half-life of 3.20 hours . If 22.8 g of the substance is currently present, what mass A0 was present 8.00 hours ago? Express your answer with the appropriate units.

User Womp
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Answer:

129 g

Step-by-step explanation:

The radioactive decay of a substance can be represented through the following expression.


A=A_(0).e^(-k.t)

where,

A is the amount of A at certain time t

A₀ is the initial amount of A

k is the rate constant

We can find k from the half-life (t1/2) using the following expression.


t_(1/2)=(ln2)/(k) \\k=(ln2)/(t_(1/2)) =(ln2)/(3.20h) =0.217h^(-1)

If 22.8 g of the substance is currently present, what mass A₀ was present 8.00 hours ago?


A=A_(0).e^(-k.t)\\22.8g = A_(0).e^{-0.217h^(-1)* 8.00h} \\A_(0)=129g

User Chintogtokh
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