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Solve the system by substitution

Solve the system by substitution-example-1
User Jmontross
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1 Answer

3 votes

Answer:

The solution to the system of equations be:


x=3,\:y=-2

Explanation:

Given the system of equations

4x-2y = 16

y = -5x+13

Solving the system of equations using the substitution method


\begin{bmatrix}4x-2y=16\\ y=-5x+13\end{bmatrix}

Substitute y = -5x+13 in 4x-2y = 16


4x-2\left(-5x+13\right)=16


4x+10x-26 = 16


14x-26 = 16

Now isolate x for
14x-26 = 16


14x-26=16

Add 26 to both sides


14x-26+26=16+26

Simplify


14x=42

Divide both sides by 14


(14x)/(14)=(42)/(14)

Simplify


x=3

For y = -5x+13

Substitute x = 3


y=-5\cdot \:3+13

Simplify


y=-2

Therefore, the solution to the system of equations be:


x=3,\:y=-2

User Gk Mohammad Emon
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