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What is an equation of the line that passes through the points (6,-5) and (3,0)

User Prudviraj
by
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2 Answers

4 votes
Gradient = (-5-0) / (6-3)
= -5 / 3
y-intercept = -5 - 6 * (-5/3)
= -5 - ( -10 )
= 5

Equation: y = -5/3 x + 5
User Aysonje
by
7.7k points
4 votes

Answer:

y+5=-5/3(x-6)

Explanation:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)

m=(0-(-5))/(3-6)

m=(0+5)/-3

m=5/-3

m=-5/3

y-(-5)=-5/3(x-6)

y+5=-5/3(x-6)

User Paul Dubs
by
7.1k points

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