Question

A 2 kg watermelon is dropped from a roof and has a speed of 5 m/s just before it hits the ground. How much kinetic energy does the watermelon have at this moment?

Answer 1

25J

Step-by-step explanation:

Given parameters:

Mass of the watermelon = 2kg

Speed before touching the ground = 5m/s

Unknown:

Kinetic energy = ?

Solution:

To solve this problem, we must understand that kinetic energy is the energy possessed by a body in motion.

K.E =
`(1)/(2)` m v²

m is the mass

v is the velocity

Now, insert the parameters and solve;

K.E =
`(1)/(2)` x 2 x 5² = 25J