Answer:
The coordinates of point P' are (7, -11)
Explanation:
we have the rule of the transformation
(x,y) —> (x+3, y-2)
That means ----> The transformation is a translation 3 units at right and 2 units down
we know that
To find out the coordinates of point P' (image of the point P) apply the rule of the translation to the pre-image P
we have
P(4,-9)
so
P(4,-9) —> P'(4+3, -9-2)
P(4,-9) —> P'(7, -11)
therefore
The coordinates of point P' are (7, -11)