Question

A student standing in a canyon yells "echo", and her voice produces a sound wave of frequency of f = 0.61 kHz. The echo takes t = 3.9 s to return to the student. Assume the speed of sound through the atmosphere at this location is v = 322 m/s.

Answer 1

`d=627.9\ m` is the distance from the obstacle of reflection.

wavelength
`\lamb=0.5279\ m`

Step-by-step explanation:

Given that:

• frequency of sound,
  `f=610\ Hz`

• time taken for the echo to be heard,
  `t=3.9\ s`

• speed of sound,
  `v=322\ m.s^(-1)`

We know,

`\rm distance = speed * time`

During an echo the sound travels the same distance back and forth.

`2d=v.t`

`2d=322* 3.9`

`d=627.9\ m` is the distance from the obstacle of reflection.

Now the wavelength of sound waves:

`\lambda=(v)/(f)`

`\lambda=(322)/(610)`

`\lamb=0.5279\ m`