Question

You wish to test the claim that p > 33 at a level of significance of a = 0.05 and are given sample 19) statistics n = 5O x = 33.3. Assume the population standard deviation is 12. Compute the value of the standardized test statistic. Round your answer to two decimal places.

Answer 1

test statistic is 0.176

Explanation:

Given Data

p>33

a=0.05

n=50

x=33.3

d(population deviation)=12

Test statistics=?

Solution

Test statistic z=(p-x)\(d/sqrt(50))

z=(33.3-30)\(12\sqrt(50))

z=0.176