Answer:
L=0.0074 mm
Step-by-step explanation:
Given that
d= 6.5 micron meter
d= 6.5 x 10⁻³ mm
Yield strength ,Sy = 73 MPa
Bond strength ,σ = 32 MPa
The fiber length given as

By putting the values


L=0.0074 mm
Therefore the minimum fiber length is 0.0074 mm.