Question

How many solutions does the system have? \begin{cases} 3x+y=8 \\\\ 2x+2y=8 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ 3x+y=8 2x+2y=8 ​ Choose 1 answer: Choose 1 answer: (Choice A, Checked) A Exactly one solution (Choice B) B No solutions (Choice C) C Infinitely many solutions

Answer 1

A

Explanation:

khan

Answer 2

This system has one solution (x=2 and y=2), then the answer is A.

Explanation:

The system of equations is:

`3x+y=8` (1)

`2x+2y=8` (2)

Let's multiply the first equation by 2 and subtract it to the second equation

`6x-2x+2y-2y=16-8`

`4x=8`

`x=2`

Using this value in (1) we can find y.

`3(2)+y=8`

`6+y=8`

`y=2`

Therefore, this system has one solution (x=2 and y=2), the answer is A.

I hope it helps you!